x^2+50x=600

Solution for x^2+50x=600 equation:

x^2+50x=600

We move all terms to the left:

x^2+50x-(600)=0

a = 1; b = 50; c = -600;
Δ = b2-4ac
Δ = 502-4·1·(-600)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-70}{2*1}=\frac{-120}{2}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+70}{2*1}=\frac{20}{2}
=10
$